Can memcpy given value as source address in c

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WebNov 3, 2012 · First, memcpy () doesn't succeed or fail in the normal sense. It just copies the data, which might cause a fault/exception if it reads outside the source array or writes outside the destination array, and it might also read or write outside one of those arrays without causing any fault/exception and just silently corrupting data. WebApr 28, 2011 · If you have larger chunk of data to store, use memcpy or memmove with that address to copy data from/to it, like this: #include int main () { const char data …

c++ - memcpy structure variables - Stack Overflow

WebJun 4, 2013 · I need a function that stores data into a void pointer. Here is a simple example of it: void saveData (void* data) { char inputData [] = "some data"; memcpy ( (char*)data, inputData, sizeof (inputData)); } However I get segmentation errors when I do this, even though it compiles just fine. My function argument has to be a void pointer because I ... WebJun 21, 2014 · The memcpy function copies n characters from the object pointed to by s2 into the object pointed to by s1. If copying takes place between objects that overlap, the … flights to chicago illinois united

Using memcpy to read two integers from a memory block

WebApr 29, 2004 · Optimizing Memcpy improves speed. Knowing a few details about your system-memory size, cache type, and bus width can pay big dividends in higher performance. The memcpy () routine in every C … WebFeb 16, 2013 · Your constant (macro) is really just a literal. As such, it has no address which could be given as parameter to memcpy or another function that expects a … WebJan 22, 2024 · Some (most) implementations of memcpy() assume that it can copy data in one specific direction which will cause data to be corrupted if areas overlap in the wrong way (e.g. if the implementation uses the "lowest address first" direction and the destination area overlaps and is at a higher address than the source, then writes to the destination ... flights to chicago illinois from pitt

Garbage value using memcpy() in c - Stack Overflow

how to implement overlap-checking memcpy in C - Stack Overflow

WebJun 24, 2015 · no, it's like *ptr = value;. memcpy takes the address of both source and destination. value must have type char * and ptr have type char ** (although you could … WebNov 27, 2024 · No, you can't [portably] use memset for that purpose, unless the desired target value is 0.memset treats the target memory region as an array of bytes, not an array of ints.. A fairly popular hack for filling a memory region with a repetitive pattern is actually based on memcpy.It critically relies on the expectation that memcpy copies data in … cheryl aggWebMay 28, 2009 · which is actually just the reverse of the memcpy () you did to get the pointer there in the first place. Although, treating the pointer as an int: int addressOfArgTwo = (unsigned int)buff; is also dangerous, if you're moving between 32-bit and 64-bit architectures, as Michael pointed out. Pointers aren't always 32-bit integers. cheryl agee

"WebJan 21, 2016 · Define you own memcpy to copy to this address space : void my_memcpy( ptr8 addr_dest, const void * src, int len ) { memcpy( my_destination_memory + … " - Can memcpy given value as source address in c

Can memcpy given value as source address in c

How to copy arrray to array using memcpy () in C

WebApr 1, 2011 · I am trying to write a stl vector in C, and I could do it if client allocating memory on the heap and pass as an element to me. But I want it to work with basic datatype and there should not be special way to pass variables on the stack or heap variables. – Avinash Apr 5, 2011 at 13:33 WebFeb 16, 2013 · As such, it has no address which could be given as parameter to memcpy or another function that expects a memory location. If you want to do this, you need to have a real constant (such as const int ), as suggested in the other answers.

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WebMar 18, 2016 · C standard library often supports this technique, memcpy being another example. A possible use case might be something along the lines of char *clone_buffer (const char *buffer, size_t size) { return memcpy (new char [size], buffer, size); } If memcpy did not return the destination buffer pointer, we'd probably have to implement the above as WebApr 17, 2012 · I am trying to read two integers, stored consecutively, from a memory block (i have a pointer void *block pointing to the contents of the block) using memcpy. The first one is read just fine using: memcpy (&test, block, sizeof (int)); I try to read the second using: memcpy (&test, block + sizeof (int), sizeof (int)); (Of course i am having ...

WebAug 3, 2015 · @PSkocik "Character type" is a term-of-art in the C standard which encompasses both single char objects and arrays of them (and probably some other stuff I don't remember off the top of my head). Regardless, the point is that char[4] and int are not compatible types and therefore you cannot use int* to access memory declared as … WebMar 12, 2013 · you can use memcpy as, memcpy(&req_byte, (buf+4), 1); this will copy fifth byte of your message to req_byte. you can vary number after (+) in source buffer to …

WebMar 28, 2013 · As a basic type safety check it makes sure the sizes of source and destination elements are the same. That's evaluated at compilation time as well. … WebSo the answer is no; the check is not necessary (or yes; you can pass zero). Share Improve this answer Follow edited Sep 22, 2012 at 10:42 answered Sep 20, 2010 at 13:32 Mike Seymour 248k 28 442 637 1 Would a pointer be considered "valid" for purposes of such a function if it pointed to the location following the last element of an array?

WebFeb 29, 2016 · You can just cast the char* to an int* and work with that seeing as you know you always have a valid 8-byte region to write to. char *data; …

WebJan 7, 2016 · memcpy () is used to copy a block of memory from a location to another. It is declared in string.h // Copies "numBytes" bytes from address "from" to address "to" void * memcpy (void *to, const void *from, size_t numBytes); Below is a sample C program to … Before memset(): GeeksForGeeks is for programming geeks. After memset(): … cheryl a grace facebookWebOct 21, 2014 · But memcpy () is about copying memory objects, not values. An object resides at a given address, and contains a given value. Taking n gives the value, … cheryl agiusWebJul 11, 2013 · Understanding the source code of memcpy () 00018 void *memcpy (void *dst, const void *src, size_t len) 00019 { 00020 size_t i; 00021 00022 /* 00023 * memcpy … cheryl adventure timeWebApr 8, 2024 · Also remember that argument in C are passed by value, meaning the value is copied into the argument variable. Modifying the argument variable (like assigning to it) … flights to chicago illinois midway airportWebThe C library function void *memcpy (void *dest, const void *src, size_t n) copies n characters from memory area src to memory area dest. Declaration Following is the … cheryl a. gemignaniWebApr 8, 2024 · You can certainly use memcpy (c1->ques, q1->ques, string_size). But it's non-standard for a string copy operation and reduces readability. – selbie Apr 8, 2024 at 3:35 Add a comment 1 In C parameters are passed by value rather than by reference. flights to chicago illinois from buffalo flights to chicago january 9